AR# 8056

説明

Description: 

How do I LOC logic to specific CLBs using Synplify and either VHDL or Verilog?

ソリューション

Using VHDL 

library IEEE; 

use IEEE.std_logic_1164.all; 

entity flops is port( 

di: in std_logic; 

ce : in std_logic; 

clk: in std_logic; 

qo: out std_logic; 

rst: in std_logic); 

end flops; 

architecture inst of flops is 

component FDCE port( D: in std_logic; 

CE: in std_logic; 

C: in std_logic; 

CLR: in std_logic; 

Q: out std_logic); 

end component; 

attribute LOC: string; 

attribute LOC of U0: label is "CLB_R2C3.S0"; 

attribute LOC of U1: label is "CLB_R2C4.S0"; 

attribute LOC of U2: label is "CLB_R6C8.S0"; 

signal q0,q1 : std_logic; 

begin 

U0 : FDCE port map(D => di, 

CE=> ce, 

C => clk, 

CLR => rst, 

Q => q0); 

U1: FDCE port map(D => q0, 

CE=> ce, 

C => clk, 

CLR => rst, 

Q => q1); 

U2: FDCE port map(D => q1, 

CE=> ce, 

C => clk, 

CLR => rst, 

Q => qo); 

end inst;

Using Verilog 

module flops (di, ce, clk, qo, rst); 

input di; 

input ce; 

input clk; 

output qo; 

input rst; 

wire q0, q1; 

FDCE u0(.D(di), 

.CE(ce), 

.C (clk), 

.CLR (rst), 

.Q (q0))/*synthesis loc="CLB_r2c3.s0" */; 

FDCE u1 (.D (q0), 

.CE(ce), 

.C (clk), 

.CLR(rst), 

.Q (q1))/* synthesis loc="CLB_r4c5.s1" */; 

FDCE u2(.D (q1), 

.CE(ce), 

.C (clk), 

.CLR (rst), 

.Q (qo)) /* synthesis loc="CLB_r6c2.s0" */; 

endmodule